exactlyOneBitIsSet(i) provides a very fast way to determine whether an integral type has exactly one bit set.
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exactlyOneBitIsSet(i) provides a very fast way to determine whether an integral type has exactly one bit set.
For unsigned and positive signed values, this is equivalent to the value being a power of two. Note that negative powers of two are not represented with a single bit set – negate it first if you want to use this routine to determine if a signed value is a negative power of two.
- See also
- atMostOneBitIsSet()
◆ exactlyOneBitIsSet() [1/11]
| bool SimTK::exactlyOneBitIsSet |
( |
unsigned char |
v | ) |
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inline |
◆ exactlyOneBitIsSet() [2/11]
| bool SimTK::exactlyOneBitIsSet |
( |
unsigned short |
v | ) |
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inline |
◆ exactlyOneBitIsSet() [3/11]
| bool SimTK::exactlyOneBitIsSet |
( |
unsigned int |
v | ) |
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inline |
◆ exactlyOneBitIsSet() [4/11]
| bool SimTK::exactlyOneBitIsSet |
( |
unsigned long |
v | ) |
|
|
inline |
◆ exactlyOneBitIsSet() [5/11]
| bool SimTK::exactlyOneBitIsSet |
( |
unsigned long long |
v | ) |
|
|
inline |
◆ exactlyOneBitIsSet() [6/11]
| bool SimTK::exactlyOneBitIsSet |
( |
signed char |
v | ) |
|
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inline |
◆ exactlyOneBitIsSet() [7/11]
| bool SimTK::exactlyOneBitIsSet |
( |
char |
v | ) |
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|
inline |
◆ exactlyOneBitIsSet() [8/11]
| bool SimTK::exactlyOneBitIsSet |
( |
short |
v | ) |
|
|
inline |
◆ exactlyOneBitIsSet() [9/11]
| bool SimTK::exactlyOneBitIsSet |
( |
int |
v | ) |
|
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inline |
◆ exactlyOneBitIsSet() [10/11]
| bool SimTK::exactlyOneBitIsSet |
( |
long |
v | ) |
|
|
inline |
◆ exactlyOneBitIsSet() [11/11]
| bool SimTK::exactlyOneBitIsSet |
( |
long long |
v | ) |
|
|
inline |
1.8.13